What is the inverse of f(x)=(x+3)^2,x>=-3 ?

The inverse of f(x)=(x+3)^2,x>=-3 is sqrt(x)-3,-sqrt(x)-3

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inverse of f(x)=(x+3)^2,x>=-3

inverse

f (x) = (x + 3)^{2}, x \geq - 3

x - 3, - x - 3

Solution steps

y = (x + 3)^{2}

Replace

x

with

y

x = (y + 3)^{2}

Solve for

y, x = (y + 3)^{2}

x - 3, - x - 3

\frac{5 x - 3}{2 x + 1}

\frac{1}{2} lo g_{3} (x) + \frac{3}{2}

f (x) = \frac{2 x + 5}{3 x - 2}

h (x) = - \frac{9 x}{4} - \frac{1}{3}

f (x) = \frac{5 x + 6}{4}

What is the inverse of f(x)=(x+3)^2,x>=-3 ?
The inverse of f(x)=(x+3)^2,x>=-3 is sqrt(x)-3,-sqrt(x)-3