What is the inverse of g(x)=2x^2+9 ?

The inverse of g(x)=2x^2+9 is sqrt((x-9)/2),-sqrt((x-9)/2)

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inverse of g(x)=2x^2+9

inverse

g (x) = 2 x^{2} + 9

\frac{x - 9}{2}, - \frac{x - 9}{2}

Solution steps

y = 2 x^{2} + 9

Replace

x

with

y

x = 2 y^{2} + 9

Solve for

y, x = 2 y^{2} + 9

\frac{x - 9}{2}, - \frac{x - 9}{2}

f (x) = 2 e^{x} - 5

f (x) = \frac{( x + 5 )}{7}

f (x) = x^{3} - 2 + \frac{1}{4}

f (x) = 2 - x^{5}

y = \frac{x}{3} + 4

What is the inverse of g(x)=2x^2+9 ?
The inverse of g(x)=2x^2+9 is sqrt((x-9)/2),-sqrt((x-9)/2)