What is the inverse of f(x)=2(x-6)^{1/3}+10 ?

The inverse of f(x)=2(x-6)^{1/3}+10 is (75x)/2+(x^3)/8-(15x^2)/4-119

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inverse of f(x)=2(x-6)^{1/3}+10

inverse

f (x) = 2 (x - 6)^{\frac{1}{3}} + 10

\frac{75 x}{2} + \frac{x ^{3}}{8} - \frac{15 x ^{2}}{4} - 119

Solution steps

y = 2 (x - 6)^{\frac{1}{3}} + 10

Replace

x

with

y

x = 2 (y - 6)^{\frac{1}{3}} + 10

Solve for

y, x = 2 (y - 6)^{\frac{1}{3}} + 10

\frac{75 x}{2} + \frac{x ^{3}}{8} - \frac{15 x ^{2}}{4} - 119

f (x) = - 2 + 6

f (x) = - 2 + 8

lo g_{5} (2 x - 1)

f (x) = \frac{1}{5} x + 3

f (x) = \frac{3 x + 5}{2 x + 1}

What is the inverse of f(x)=2(x-6)^{1/3}+10 ?
The inverse of f(x)=2(x-6)^{1/3}+10 is (75x)/2+(x^3)/8-(15x^2)/4-119