What is the inverse of f(x)=x^2-6x+1 ?

The inverse of f(x)=x^2-6x+1 is 3+sqrt(x+8),3-sqrt(x+8)

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inverse of f(x)=x^2-6x+1

inverse

f (x) = x^{2} - 6 x + 1

3 + x + 8, 3 - x + 8

Solution steps

y = x^{2} - 6 x + 1

Replace

x

with

y

x = y^{2} - 6 y + 1

Solve for

y, x = y^{2} - 6 y + 1

3 + x + 8, 3 - x + 8

f (x) = - 2 - x + 1

f (x) = sin (x) + 3

f (x) = \frac{- 2}{x + 3} + 5

f (x) = \frac{3 - 2 x}{3 x - 2}

f (x) = \frac{9 x}{4 x - 3}

What is the inverse of f(x)=x^2-6x+1 ?
The inverse of f(x)=x^2-6x+1 is 3+sqrt(x+8),3-sqrt(x+8)