What is the inverse of f(x)=((3x+3))/(3x-7) ?

The inverse of f(x)=((3x+3))/(3x-7) is (3+7x)/(3(-1+x))

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inverse of f(x)=((3x+3))/(3x-7)

inverse

f (x) = \frac{( 3 x + 3 )}{3 x - 7}

\frac{3 + 7 x}{3 ( - 1 + x )}

Solution steps

y = \frac{3 x + 3}{3 x - 7}

Replace

x

with

y

x = \frac{3 y + 3}{3 y - 7}

Solve for

y, x = \frac{3 y + 3}{3 y - 7}

\frac{3 + 7 x}{3 ( - 1 + x )}

\frac{32}{5} - \frac{3}{10} x

f (x) = e^{x - 3} - 1

f (x) = x^{2} + 2 x, x \geq 0

f (x) = \frac{( x - 3 )}{x + 3}

f (x) = lo g_{2} (4 x - 10)

What is the inverse of f(x)=((3x+3))/(3x-7) ?
The inverse of f(x)=((3x+3))/(3x-7) is (3+7x)/(3(-1+x))