What is the inverse of f(x)=(x-2)/(2x+1) ?

The inverse of f(x)=(x-2)/(2x+1) is (-2-x)/(2x-1)

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inverse of f(x)=(x-2)/(2x+1)

inverse

f (x) = \frac{x - 2}{2 x + 1}

\frac{- 2 - x}{2 x - 1}

Solution steps

y = \frac{x - 2}{2 x + 1}

Replace

x

with

y

x = \frac{y - 2}{2 y + 1}

Solve for

y, x = \frac{y - 2}{2 y + 1}

\frac{- 2 - x}{2 x - 1}

Y (x) = lo g_{10} (x + 4)

\frac{3 x x}{8}

y = 6 x, x = 3

f (x) = \frac{x + 1}{2} - 3

tan (\frac{1}{3})

What is the inverse of f(x)=(x-2)/(2x+1) ?
The inverse of f(x)=(x-2)/(2x+1) is (-2-x)/(2x-1)