What is the inverse of f(x)=x^2-x+1 ?

The inverse of f(x)=x^2-x+1 is (1+sqrt(4x-3))/2 ,(1-sqrt(4x-3))/2

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inverse of f(x)=x^2-x+1

inverse

f (x) = x^{2} - x + 1

\frac{1 + 4 x - 3}{2}, \frac{1 - 4 x - 3}{2}

Solution steps

y = x^{2} - x + 1

Replace

x

with

y

x = y^{2} - y + 1

Solve for

y, x = y^{2} - y + 1

\frac{1 + 4 x - 3}{2}, \frac{1 - 4 x - 3}{2}

f (x) = 4 x^{3} - 13

f (x) = \frac{3 x}{x - 4}

f (x) = 30 - 30 e^{- l n (10) \cdot x}

f (x) = arcsin (\frac{x ^{2} - 1}{x ^{2} + 1})

2 - lo g_{10} (x)

What is the inverse of f(x)=x^2-x+1 ?
The inverse of f(x)=x^2-x+1 is (1+sqrt(4x-3))/2 ,(1-sqrt(4x-3))/2