What is the inverse of f(x)=4x^{-3/5} ?

The inverse of f(x)=4x^{-3/5} is (8*2^{1/3})/(x^{5/3)}

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inverse of f(x)=4x^{-3/5}

inverse

f (x) = 4 x^{- \frac{3}{5}}

\frac{8 \cdot 2 ^{\frac{1}{3}}}{x ^{\frac{5}{3}}}

Solution steps

y = 4 x^{- \frac{3}{5}}

Replace

x

with

y

x = 4 y^{- \frac{3}{5}}

Solve for

y, x = 4 y^{- \frac{3}{5}}

\frac{8 \cdot 2 ^{\frac{1}{3}}}{x ^{\frac{5}{3}}}

- x - 5 - 2

f (x) = 11 - x^{3}

g (x) = (x + 3)^{3}

f (x) = - 9 x + 5

f (x) = \frac{1}{2} (x + 6)^{2} - 8

What is the inverse of f(x)=4x^{-3/5} ?
The inverse of f(x)=4x^{-3/5} is (8*2^{1/3})/(x^{5/3)}