What is the inverse of f(x)=((x+2))/((x-1)) ?

The inverse of f(x)=((x+2))/((x-1)) is (2+x)/(x-1)

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inverse of f(x)=((x+2))/((x-1))

inverse

f (x) = \frac{( x + 2 )}{( x - 1 )}

\frac{2 + x}{x - 1}

Solution steps

y = \frac{x + 2}{x - 1}

Replace

x

with

y

x = \frac{y + 2}{y - 1}

Solve for

y, x = \frac{y + 2}{y - 1}

\frac{2 + x}{x - 1}

\frac{x}{5 x - 7}

f (x) = \frac{1}{6} (x - 8)

x^{2} - 6 x + 8

x^{2} - 6 x + 9

What is the inverse of f(x)=((x+2))/((x-1)) ?
The inverse of f(x)=((x+2))/((x-1)) is (2+x)/(x-1)