What is the inverse of h(x)=((x-2))/((x+3)) ?

The inverse of h(x)=((x-2))/((x+3)) is (-2-3x)/(x-1)

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inverse of h(x)=((x-2))/((x+3))

inverse

h (x) = \frac{( x - 2 )}{( x + 3 )}

\frac{- 2 - 3 x}{x - 1}

Solution steps

y = \frac{x - 2}{x + 3}

Replace

x

with

y

x = \frac{y - 2}{y + 3}

Solve for

y, x = \frac{y - 2}{y + 3}

\frac{- 2 - 3 x}{x - 1}

5 \cdot 2^{1 - x} - 1

f (x) = ln (sin (x))

f (x) = 5 ln (2 x) + 3

f (x) = 2 (5^{x} - 8)

y = - 1 - x + 3

What is the inverse of h(x)=((x-2))/((x+3)) ?
The inverse of h(x)=((x-2))/((x+3)) is (-2-3x)/(x-1)