What is the domain of f(x)=sqrt(9-x^2)*sqrt(x+1) ?

The domain of f(x)=sqrt(9-x^2)*sqrt(x+1) is -1<= x<= 3

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domain of f(x)=sqrt(9-x^2)*sqrt(x+1)

domain

f (x) = 9 - x^{2} \cdot x + 1

- 1 \leq x \leq 3

Interval Notation

[- 1, 3]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 3

The function domain

- 1 \leq x \leq 3

3 x^{4} + 4 x^{3}

f (x) = \frac{x - 1}{( x + 3 ) ( x - 2 )}

f (x) = 1 0^{(x - 2)} - 5

(x - 8) 2 x^{2}

f (x) = \frac{10 x ^{2}}{2 x ^{2} + 1}

What is the domain of f(x)=sqrt(9-x^2)*sqrt(x+1) ?
The domain of f(x)=sqrt(9-x^2)*sqrt(x+1) is -1<= x<= 3