What is the inverse of f(x)=(x-7)^2,x>= 7 ?

The inverse of f(x)=(x-7)^2,x>= 7 is sqrt(x)+7,-sqrt(x)+7

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inverse of f(x)=(x-7)^2,x>= 7

inverse

f (x) = (x - 7)^{2}, x \geq 7

x + 7, - x + 7

Solution steps

y = (x - 7)^{2}

Replace

x

with

y

x = (y - 7)^{2}

Solve for

y, x = (y - 7)^{2}

x + 7, - x + 7

\frac{1}{5} x - 3

f (x) = \frac{3 x + 1}{2 - x}

f (x) = \frac{3 x + 4}{8}

\frac{x + 3}{5 x - 2}

W (x) = 715 x + 2

What is the inverse of f(x)=(x-7)^2,x>= 7 ?
The inverse of f(x)=(x-7)^2,x>= 7 is sqrt(x)+7,-sqrt(x)+7