What is the inverse of y=sqrt(x^2+6x) ?

The inverse of y=sqrt(x^2+6x) is -3+sqrt(x^2+9),-sqrt(x^2+9)-3

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inverse of y=sqrt(x^2+6x)

inverse

y = x^{2} + 6 x

- 3 + x^{2} + 9, - x^{2} + 9 - 3

Solution steps

y = x^{2} + 6 x

Replace

x

with

y

x = y^{2} + 6 y

Solve for

y, x = y^{2} + 6 y

- 3 + x^{2} + 9, - x^{2} + 9 - 3

3 - x^{3}

\frac{2 x}{1 + 0.01 x}

f (x) = 1 - sin (x)

f (x) = \frac{2 e ^{x} - 4}{12 e ^{x} + 11}

4 tan (2 x)

What is the inverse of y=sqrt(x^2+6x) ?
The inverse of y=sqrt(x^2+6x) is -3+sqrt(x^2+9),-sqrt(x^2+9)-3