What is the inverse of f(x)=190-4.9x^2 ?

The inverse of f(x)=190-4.9x^2 is sqrt(-(10x-1900)/(49)),-sqrt(-(10x-1900)/(49))

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inverse of f(x)=190-4.9x^2

inverse

f (x) = 190 - 4.9 x^{2}

- \frac{10 x - 1900}{49}, - - \frac{10 x - 1900}{49}

Solution steps

y = 190 - 4.9 x^{2}

Replace

x

with

y

x = 190 - 4.9 y^{2}

Solve for

y, x = 190 - 4.9 y^{2}

- \frac{10 x - 1900}{49}, - - \frac{10 x - 1900}{49}

f (x) = \frac{- 4}{7} x - \frac{16}{7}

f (x) = lo g_{2} (18 x - 4)

f (x) = ln (x^{5})

\frac{x - 3}{x + 4}

f (x) = 2 ln (x - 3)

What is the inverse of f(x)=190-4.9x^2 ?
The inverse of f(x)=190-4.9x^2 is sqrt(-(10x-1900)/(49)),-sqrt(-(10x-1900)/(49))