What is the inverse of f(x)=(x+1)/x ,x\ne 0 ?

The inverse of f(x)=(x+1)/x ,x\ne 0 is 1/(x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x+1)/x ,x\ne 0

inverse

f (x) = \frac{x + 1}{x}, x \neq = 0

\frac{1}{x - 1}

Solution steps

y = \frac{x + 1}{x}

Replace

x

with

y

x = \frac{y + 1}{y}

Solve for

y, x = \frac{y + 1}{y}

\frac{1}{x - 1}

- \frac{3}{x + 4}

f (x) = \frac{4 x - 2}{x + 3}

f (x) = 3 (x - 5) + 8

f (x) = \frac{9}{x + 5}

What is the inverse of f(x)=(x+1)/x ,x\ne 0 ?
The inverse of f(x)=(x+1)/x ,x\ne 0 is 1/(x-1)