What is the inverse of f(x)=((3x^2+4))/8 ?

The inverse of f(x)=((3x^2+4))/8 is sqrt((8x-4)/3),-sqrt((8x-4)/3)

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inverse of f(x)=((3x^2+4))/8

inverse

f (x) = \frac{( 3 x ^{2} + 4 )}{8}

\frac{8 x - 4}{3}, - \frac{8 x - 4}{3}

Solution steps

y = \frac{3 x ^{2} + 4}{8}

Replace

x

with

y

x = \frac{3 y ^{2} + 4}{8}

Solve for

y, x = \frac{3 y ^{2} + 4}{8}

\frac{8 x - 4}{3}, - \frac{8 x - 4}{3}

7 - x

f (x) = 3 x - 2 + 1

\frac{d}{d} - 2 x - 3

f (x) = \frac{5 x + 6}{x - 1}

f (x) = - \frac{1}{3} x + 6

What is the inverse of f(x)=((3x^2+4))/8 ?
The inverse of f(x)=((3x^2+4))/8 is sqrt((8x-4)/3),-sqrt((8x-4)/3)