What is the inverse of f(x)=-16x^2 ?

The inverse of f(x)=-16x^2 is sqrt(-x/(16)),-sqrt(-x/(16))

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inverse of f(x)=-16x^2

inverse

f (x) = - 16 x^{2}

- \frac{x}{16}, - - \frac{x}{16}

Solution steps

y = - 16 x^{2}

Replace

x

with

y

x = - 16 y^{2}

Solve for

y, x = - 16 y^{2}

- \frac{x}{16}, - - \frac{x}{16}

f (x) = 6 x + 1

\frac{1}{2} x + \frac{3}{2}

f (x) = 3 x + 24

7 x^{2} + 3

\frac{8 x - 3}{5}

What is the inverse of f(x)=-16x^2 ?
The inverse of f(x)=-16x^2 is sqrt(-x/(16)),-sqrt(-x/(16))