What is the inverse of (x^2-2x+4)/(x-2) ?

The inverse of (x^2-2x+4)/(x-2) is (2+x+sqrt(x^2-4x-12))/2 ,(2+x-sqrt(x^2-4x-12))/2

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inverse of (x^2-2x+4)/(x-2)

inverse

\frac{x ^{2} - 2 x + 4}{x - 2}

\frac{2 + x + x ^{2} - 4 x - 12}{2}, \frac{2 + x - x ^{2} - 4 x - 12}{2}

Solution steps

y = \frac{x ^{2} - 2 x + 4}{x - 2}

Replace

x

with

y

x = \frac{y ^{2} - 2 y + 4}{y - 2}

Solve for

y, x = \frac{y ^{2} - 2 y + 4}{y - 2}

\frac{2 + x + x ^{2} - 4 x - 12}{2}, \frac{2 + x - x ^{2} - 4 x - 12}{2}

2 x - 7

f (x) = \frac{x ^{3} - 2}{4}

f (x) = \frac{( 5 x - 7 )}{x + 2}

f (x) = \frac{( 3 x + 4 )}{5}

f (x) = \frac{1}{( x ^{2} - 3 x )}

What is the inverse of (x^2-2x+4)/(x-2) ?
The inverse of (x^2-2x+4)/(x-2) is (2+x+sqrt(x^2-4x-12))/2 ,(2+x-sqrt(x^2-4x-12))/2