What is the inverse of f(x)=1+3sqrt(x) ?

The inverse of f(x)=1+3sqrt(x) is (x^2)/9-(2x)/9+1/9

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inverse of f(x)=1+3sqrt(x)

inverse

f (x) = 1 + 3 x

\frac{x ^{2}}{9} - \frac{2 x}{9} + \frac{1}{9}

Solution steps

y = 1 + 3 x

Replace

x

with

y

x = 1 + 3 y

Solve for

y, x = 1 + 3 y

\frac{x ^{2}}{9} - \frac{2 x}{9} + \frac{1}{9}

\frac{6}{x + 1}

f (x) = \frac{x}{4} + 5, - 3 \leq x \leq 4

- 9 x

g (x) = - \frac{1}{2} x - 2

What is the inverse of f(x)=1+3sqrt(x) ?
The inverse of f(x)=1+3sqrt(x) is (x^2)/9-(2x)/9+1/9