What is the inverse of f(x)=(1-3x)/(2x+1) ?

The inverse of f(x)=(1-3x)/(2x+1) is (1-x)/(2x+3)

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inverse of f(x)=(1-3x)/(2x+1)

inverse

f (x) = \frac{1 - 3 x}{2 x + 1}

\frac{1 - x}{2 x + 3}

Solution steps

y = \frac{1 - 3 x}{2 x + 1}

Replace

x

with

y

x = \frac{1 - 3 y}{2 y + 1}

Solve for

y, x = \frac{1 - 3 y}{2 y + 1}

\frac{1 - x}{2 x + 3}

f (x) = x \frac{1}{3} - 9

- \frac{2}{x + 1}

f (x) = \frac{2 x - 9}{3}

k

lo g_{10} (- 6.2)

What is the inverse of f(x)=(1-3x)/(2x+1) ?
The inverse of f(x)=(1-3x)/(2x+1) is (1-x)/(2x+3)