What is the inverse of f(x)= 2/(sqrt(x+1)) ?

The inverse of f(x)= 2/(sqrt(x+1)) is 4/(x^2)-1

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inverse of f(x)= 2/(sqrt(x+1))

inverse

f (x) = \frac{2}{x + 1}

\frac{4}{x ^{2}} - 1

Solution steps

y = \frac{2}{x + 1}

Replace

x

with

y

x = \frac{2}{y + 1}

Solve for

y, x = \frac{2}{y + 1}

\frac{4}{x ^{2}} - 1

3 x - 15

f (x) = \frac{5 x}{x ^{2} - 16}

f (x) = 6 x^{5} - 3

lo g_{2} (x - 10)

\frac{4 x}{x - 8}

What is the inverse of f(x)= 2/(sqrt(x+1)) ?
The inverse of f(x)= 2/(sqrt(x+1)) is 4/(x^2)-1