What is the inverse of f(x)=x^4-1 ?

The inverse of f(x)=x^4-1 is \sqrt[4]{x+1},-\sqrt[4]{x+1}

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inverse of f(x)=x^4-1

inverse

f (x) = x^{4} - 1

Solution steps

y = x^{4} - 1

Replace

x

with

y

x = y^{4} - 1

Solve for

y, x = y^{4} - 1

y = \frac{x}{5} + 8

f (x) = x - 1 - 3

1 - cos (x), 0 \leq x \leq 2 π

y = \frac{- 3 x ^{2} - 1}{x ^{2} - 1}

What is the inverse of f(x)=x^4-1 ?
The inverse of f(x)=x^4-1 is \sqrt[4]{x+1},-\sqrt[4]{x+1}