What is the inverse of f(x)=-x^2+x+2 ?

The inverse of f(x)=-x^2+x+2 is -(-1+sqrt(-4x+9))/2 ,-(-1-sqrt(-4x+9))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=-x^2+x+2

inverse

f (x) = - x^{2} + x + 2

- \frac{- 1 + - 4 x + 9}{2}, - \frac{- 1 - - 4 x + 9}{2}

Solution steps

y = - x^{2} + x + 2

Replace

x

with

y

x = - y^{2} + y + 2

Solve for

y, x = - y^{2} + y + 2

- \frac{- 1 + - 4 x + 9}{2}, - \frac{- 1 - - 4 x + 9}{2}

f (x) = \frac{3}{5} x - 1

f (x) = sin (0) + 1

f (x) = \frac{( x - 7 )}{x + 7}

f (x) = 4 e^{x} - e^{- x}

What is the inverse of f(x)=-x^2+x+2 ?
The inverse of f(x)=-x^2+x+2 is -(-1+sqrt(-4x+9))/2 ,-(-1-sqrt(-4x+9))/2