What is the inverse of f(s)= 1/(s^3+a^3) ?

The inverse of f(s)= 1/(s^3+a^3) is cube root of (1-a^3s)/s

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inverse of f(s)= 1/(s^3+a^3)

inverse

f (s) = \frac{1}{s ^{3} + a ^{3}}

Solution steps

y = \frac{1}{s ^{3} + a ^{3}}

Replace

s

with

y

s = \frac{1}{y ^{3} + a ^{3}}

Solve for

y, s = \frac{1}{y ^{3} + a ^{3}}

f (x) = 5 x^{2} + 7

f (x) = 5 x^{2} + 4

4 (x - 11)^{2}

f (x) = 5 x - 27

f (x) = \frac{8 x}{3 x + 1}

What is the inverse of f(s)= 1/(s^3+a^3) ?
The inverse of f(s)= 1/(s^3+a^3) is cube root of (1-a^3s)/s