What is the inverse of f(x)=2+log_{2}(1-x) ?

The inverse of f(x)=2+log_{2}(1-x) is -2^{x-2}+1

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inverse of f(x)=2+log_{2}(1-x)

inverse

f (x) = 2 + lo g_{2} (1 - x)

- 2^{x - 2} + 1

Solution steps

y = 2 + lo g_{2} (1 - x)

Replace

x

with

y

x = 2 + lo g_{2} (1 - y)

Solve for

y, x = 2 + lo g_{2} (1 - y)

- 2^{x - 2} + 1

y = - 3 x + 12

g (x) = \frac{3 x + 4}{2 x - 5}

69 - 15 x

f (x) = n^{5} + 3

f (x) = 6 x - 24

What is the inverse of f(x)=2+log_{2}(1-x) ?
The inverse of f(x)=2+log_{2}(1-x) is -2^{x-2}+1