What is the inverse of f(x)= 1/4 x^2-2 ?

The inverse of f(x)= 1/4 x^2-2 is 2sqrt(x+2),-2sqrt(x+2)

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inverse of f(x)= 1/4 x^2-2

inverse

f (x) = \frac{1}{4} x^{2} - 2

2 x + 2, - 2 x + 2

Solution steps

y = \frac{1}{4} x^{2} - 2

Replace

x

with

y

x = \frac{1}{4} y^{2} - 2

Solve for

y, x = \frac{1}{4} y^{2} - 2

2 x + 2, - 2 x + 2

f (x) = x + \frac{2}{5}

f (x) = 8 + arctan (x + 1)

f (x) = \frac{1}{- x + 2} - 2

{x^{2} - 3 : x \geq 0}

What is the inverse of f(x)= 1/4 x^2-2 ?
The inverse of f(x)= 1/4 x^2-2 is 2sqrt(x+2),-2sqrt(x+2)