What is the inverse of d/d 7x+sqrt(x+50) ?

The inverse of d/d 7x+sqrt(x+50) is (14x+1+sqrt(28x+9801))/(98),(14x+1-sqrt(28x+9801))/(98)

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inverse of d/d 7x+sqrt(x+50)

inverse

\frac{d}{d} 7 x + x + 50

\frac{14 x + 1 + 28 x + 9801}{98}, \frac{14 x + 1 - 28 x + 9801}{98}

Solution steps

y = \frac{d}{d} \cdot 7 x + x + 50

Replace

x

with

y

x = \frac{d}{d} \cdot 7 y + y + 50

Solve for

y, x = \frac{d}{d} 7 y + y + 50

\frac{14 x + 1 + 28 x + 9801}{98}, \frac{14 x + 1 - 28 x + 9801}{98}

f (x) = x + 3 + 1

f (x) = \frac{8 - 5 x}{3}

f (x) = - \frac{7}{( 1 + 4 x )}

9.8 (\frac{T}{2 π})^{2}

What is the inverse of d/d 7x+sqrt(x+50) ?
The inverse of d/d 7x+sqrt(x+50) is (14x+1+sqrt(28x+9801))/(98),(14x+1-sqrt(28x+9801))/(98)