What is the inverse of sqrt(x^2-4)-y=0 ?

The inverse of sqrt(x^2-4)-y=0 is sqrt(x^2+4),-sqrt(x^2+4)

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inverse of sqrt(x^2-4)-y=0

inverse

x^{2} - 4 - y = 0

x^{2} + 4, - x^{2} + 4

Solution steps

y = x^{2} - 4

Replace

x

with

y

x = y^{2} - 4

Solve for

y, x = y^{2} - 4

x^{2} + 4, - x^{2} + 4

f (x) = \frac{x - 2}{x ^{2} - 4}

f (x) = 15 x + 6

f (x) = \frac{8 x + 9}{3 x - 8}

f (x) = 8 x - 72

What is the inverse of sqrt(x^2-4)-y=0 ?
The inverse of sqrt(x^2-4)-y=0 is sqrt(x^2+4),-sqrt(x^2+4)