What is the inverse of f(x)=x-((1-x^2)/(2x)) ?

The inverse of f(x)=x-((1-x^2)/(2x)) is (x+sqrt(x^2+3))/3 ,(x-sqrt(x^2+3))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=x-((1-x^2)/(2x))

inverse

f (x) = x - (\frac{1 - x ^{2}}{2 x})

\frac{x + x ^{2} + 3}{3}, \frac{x - x ^{2} + 3}{3}

Solution steps

y = x - \frac{1 - x ^{2}}{2 x}

Replace

x

with

y

x = y - \frac{1 - y ^{2}}{2 y}

Solve for

y, x = y - \frac{1 - y ^{2}}{2 y}

\frac{x + x ^{2} + 3}{3}, \frac{x - x ^{2} + 3}{3}

f (x) = (\frac{1}{10})^{x}

f (x) = sin (\frac{x}{2})

h (x) = lo g_{10} (2 x + 3)

f (x) = (x + 4)^{3} + 8

\frac{21}{x ^{2}}

What is the inverse of f(x)=x-((1-x^2)/(2x)) ?
The inverse of f(x)=x-((1-x^2)/(2x)) is (x+sqrt(x^2+3))/3 ,(x-sqrt(x^2+3))/3