What is the inverse of f(x)=(x^2)/4-1 ?

The inverse of f(x)=(x^2)/4-1 is 2sqrt(x+1),-2sqrt(x+1)

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inverse of f(x)=(x^2)/4-1

inverse

f (x) = \frac{x ^{2}}{4} - 1

2 x + 1, - 2 x + 1

Solution steps

y = \frac{x ^{2}}{4} - 1

Replace

x

with

y

x = \frac{y ^{2}}{4} - 1

Solve for

y, x = \frac{y ^{2}}{4} - 1

2 x + 1, - 2 x + 1

f (x) = 8 x + 24

f (x) = \frac{( 3 x - 7 )}{( 4 x + 3 )}

f (x) = - \frac{x ^{2}}{4} + x

lo g_{\frac{1}{2}} (x + 4)

f (x) = 7 e^{- 4 x} + 2

What is the inverse of f(x)=(x^2)/4-1 ?
The inverse of f(x)=(x^2)/4-1 is 2sqrt(x+1),-2sqrt(x+1)