What is the inverse of f(x)=(3x-1)/(4-2x) ?

The inverse of f(x)=(3x-1)/(4-2x) is -(-1-4x)/(3+2x)

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inverse of f(x)=(3x-1)/(4-2x)

inverse

f (x) = \frac{3 x - 1}{4 - 2 x}

- \frac{- 1 - 4 x}{3 + 2 x}

Solution steps

y = \frac{3 x - 1}{4 - 2 x}

Replace

x

with

y

x = \frac{3 y - 1}{4 - 2 y}

Solve for

y, x = \frac{3 y - 1}{4 - 2 y}

- \frac{- 1 - 4 x}{3 + 2 x}

y = \frac{5 x}{6} + 1

f (x) = (x + 2) 2

f (x) = \frac{9 x + 7}{2}

7 x + 6

f (x) = (ln (x))^{3}

What is the inverse of f(x)=(3x-1)/(4-2x) ?
The inverse of f(x)=(3x-1)/(4-2x) is -(-1-4x)/(3+2x)