What is the inverse of f(x)=(x+20)/(20x-1) ?

The inverse of f(x)=(x+20)/(20x-1) is (20+x)/(20x-1)

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inverse of f(x)=(x+20)/(20x-1)

inverse

f (x) = \frac{x + 20}{20 x - 1}

\frac{20 + x}{20 x - 1}

Solution steps

y = \frac{x + 20}{20 x - 1}

Replace

x

with

y

x = \frac{y + 20}{20 y - 1}

Solve for

y, x = \frac{y + 20}{20 y - 1}

\frac{20 + x}{20 x - 1}

y = - 3 x + 5

(y + 9) = \frac{5}{7} (x - 7)

f (x) = 2 x + 3 - 4

f (x) = \frac{( x ^{2} - 16 )}{x ^{2} - 6 x + 8}

f (x) = 9 - x^{2} + x + 3

What is the inverse of f(x)=(x+20)/(20x-1) ?
The inverse of f(x)=(x+20)/(20x-1) is (20+x)/(20x-1)