What is the inverse of f(x)=((x+1))/((x-4)) ?

The inverse of f(x)=((x+1))/((x-4)) is (1+4x)/(x-1)

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inverse of f(x)=((x+1))/((x-4))

inverse

f (x) = \frac{( x + 1 )}{( x - 4 )}

\frac{1 + 4 x}{x - 1}

Solution steps

y = \frac{x + 1}{x - 4}

Replace

x

with

y

x = \frac{y + 1}{y - 4}

Solve for

y, x = \frac{y + 1}{y - 4}

\frac{1 + 4 x}{x - 1}

y = \frac{1}{3} x^{3}

f (x) = 11 x + 15

y = \frac{7}{x}

3^{x - 2}

f (x) = \frac{- 25 + 3 x}{5}

What is the inverse of f(x)=((x+1))/((x-4)) ?
The inverse of f(x)=((x+1))/((x-4)) is (1+4x)/(x-1)