What is the domain of (x^2+1)/(x-3) ?

The domain of (x^2+1)/(x-3) is x 3

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domain of (x^2+1)/(x-3)

domain

\frac{x ^{2} + 1}{x - 3}

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

\frac{2 x ^{2} - 6 x + 4}{- 3 x - 5}

\frac{2 x ^{2}}{x ^{2} - 1}

\frac{1 - 2 x}{x - 2}

f (x) = \frac{x + 2}{x ^{2} - 121}

\frac{4 a ^{2} - 20 a + 25}{25 - 4 a ^{2}}

What is the domain of (x^2+1)/(x-3) ?
The domain of (x^2+1)/(x-3) is x<3\lor x>3