What is the domain of y=(x^2+1)/(x-3) ?

The domain of y=(x^2+1)/(x-3) is x 3

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domain of y=(x^2+1)/(x-3)

domain

y = \frac{x ^{2} + 1}{x - 3}

x < 3 or x > 3

Interval Notation

(- \infty, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3

The function domain

x < 3 or x > 3

f (x) = x (x - 3)^{- \frac{1}{4}}

f (x) = \frac{x - 2 + 2}{x ^{2} - 9}

∣ - 3 x ∣

y = \frac{2 x ^{2} - 6 x + 4}{- 3 x - 5}

\frac{2 x + 3}{x ^{2} + 3 x + 2}

What is the domain of y=(x^2+1)/(x-3) ?
The domain of y=(x^2+1)/(x-3) is x<3\lor x>3