What is the domain of f(x)= 1/(x^2-4x+3) ?

The domain of f(x)= 1/(x^2-4x+3) is x 3

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domain of f(x)= 1/(x^2-4x+3)

domain

f (x) = \frac{1}{x ^{2} - 4 x + 3}

x < 1 or 1 < x < 3 or x > 3

Interval Notation

(- \infty, 1) \cup (1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = 1

The function domain

x < 1 or 1 < x < 3 or x > 3

f (x) = \frac{2 - x}{3 x ^{3} + 4 x ^{2}}

f (x) = \frac{x ^{5} + 1}{( x ^{2} - 1 ) ^{2}}

f (x) = lo g_{10} (6 x - 1)

f (x) = 7 x - 21 + \frac{x}{x - 8}

f (x) = x 4 - x

What is the domain of f(x)= 1/(x^2-4x+3) ?
The domain of f(x)= 1/(x^2-4x+3) is x<1\lor 1<x<3\lor x>3