What is the domain of f(x)=sqrt((x^2-1)/(x^3+x)) ?

The domain of f(x)=sqrt((x^2-1)/(x^3+x)) is -1 = 1

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domain of f(x)=sqrt((x^2-1)/(x^3+x))

domain

f (x) = \frac{x ^{2} - 1}{x ^{3} + x}

- 1 \leq x < 0 or x \geq 1

Interval Notation

[- 1, 0) \cup [1, \infty)

Solution steps

Find non-negative values for radicals:

- 1 \leq x < 0 or x \geq 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 1 \leq x < 0 or x \geq 1

5 x + 2

\frac{5 x}{14 - x}

f (x) = (x^{2} - 4)^{\frac{5}{3}}

f (x) = \frac{x ^{3} + x}{x ^{2} - 1}

\frac{( b - 2 ) ^{2}}{( 2 - b ) ^{2}}

What is the domain of f(x)=sqrt((x^2-1)/(x^3+x)) ?
The domain of f(x)=sqrt((x^2-1)/(x^3+x)) is -1<= x<0\lor x>= 1