What is the domain of f(x)=3+sqrt(x+1) ?

The domain of f(x)=3+sqrt(x+1) is x>=-1

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domain of f(x)=3+sqrt(x+1)

domain

f (x) = 3 + x + 1

x \geq - 1

Interval Notation

[- 1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 1

The function domain

x \geq - 1

ln (4 + ln (x))

f (x) = sin^{2} (x) - \frac{1}{4}

f (x) = \frac{x}{x - 5}

f (x) = \frac{1}{- 4 x ^{2} - 20 x - 21}

ln (x + 5)

What is the domain of f(x)=3+sqrt(x+1) ?
The domain of f(x)=3+sqrt(x+1) is x>=-1