What is the domain of f(x)=sqrt(x-4/x) ?

The domain of f(x)=sqrt(x-4/x) is -2 = 2

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domain of f(x)=sqrt(x-4/x)

domain

f (x) = x - \frac{4}{x}

- 2 \leq x < 0 or x \geq 2

Interval Notation

[- 2, 0) \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

- 2 \leq x < 0 or x \geq 2

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 2 \leq x < 0 or x \geq 2

y = \frac{1}{x - 3}

f (x) = x + ln (x^{2} - 3)

f (x) = e^{x^{2} - 3}

5 x

f (x) = x^{2} + 9, x \geq 0

What is the domain of f(x)=sqrt(x-4/x) ?
The domain of f(x)=sqrt(x-4/x) is -2<= x<0\lor x>= 2