What is the domain of f(x)=sqrt(1-x^2) ?

The domain of f(x)=sqrt(1-x^2) is -1<= x<= 1

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domain of f(x)=sqrt(1-x^2)

domain

f (x) = 1 - x^{2}

- 1 \leq x \leq 1

Interval Notation

[- 1, 1]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

The function domain

- 1 \leq x \leq 1

f (x) = \frac{2}{2 x + 8}

f (x) = 3 x^{3} + 3 x^{2} + 3

(2.2) (6.6)

f (x) = e^{2 x} + e^{- x}

f (x) = (x - 5)^{2} + (y + 2)^{2} = 16

What is the domain of f(x)=sqrt(1-x^2) ?
The domain of f(x)=sqrt(1-x^2) is -1<= x<= 1