What is the domain of f(x)=(x^2)/(sqrt(x^2-1)) ?

The domain of f(x)=(x^2)/(sqrt(x^2-1)) is x 1

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domain of f(x)=(x^2)/(sqrt(x^2-1))

domain

f (x) = \frac{x ^{2}}{x ^{2} - 1}

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 1 or x \geq 1

Find undefined (singularity) points:

x = 1, x = - 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 1

f (x) = \frac{x - 1}{x - 2}

f (x) = 3 - x + \frac{1}{x + 2}

{sin (x) : - 4 π < x < 0, 2 x : x \geq 0}

f (x) = lo g_{10} (x - 2)

f (x) = lo g_{10} (x^{2} - 4)

What is the domain of f(x)=(x^2)/(sqrt(x^2-1)) ?
The domain of f(x)=(x^2)/(sqrt(x^2-1)) is x<-1\lor x>1