What is the domain of f(x)= 1/(x^2+4) ?

The domain of f(x)= 1/(x^2+4) is -infinity <x<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)= 1/(x^2+4)

domain

f (x) = \frac{1}{x ^{2} + 4}

- \infty < x < \infty

Interval Notation

(- \infty, \infty)

Solution steps

The function has no undefined points nor domain constraints. Therefore, the domain is

- \infty < x < \infty

f (x) = lo g_{10} (x^{2} - 9)

f (x) = \frac{1 + x}{x ^{2} - 4}

\frac{x ^{3}}{x + 1}

f (x) = \frac{1 - x ^{2}}{x ^{3} + x}

f (x) = 10 x - 4

What is the domain of f(x)= 1/(x^2+4) ?
The domain of f(x)= 1/(x^2+4) is -infinity <x<infinity