What is the domain of f(t)=((x^2-1))/(2x+3) ?

The domain of f(t)=((x^2-1))/(2x+3) is x -3/2

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domain of f(t)=((x^2-1))/(2x+3)

domain

f (t) = \frac{( x ^{2} - 1 )}{2 x + 3}

x < - \frac{3}{2} or x > - \frac{3}{2}

Interval Notation

(- \infty, - \frac{3}{2}) \cup (- \frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = - \frac{3}{2}

The function domain

x < - \frac{3}{2} or x > - \frac{3}{2}

\frac{1}{1 + 2 I}

y = \frac{2 x + 1}{x ^{2} - x + 1}

\frac{9}{x ^{2} - 7 x}

f (x) = \frac{3}{x - 1}

f (x) = x ln (2 x)

What is the domain of f(t)=((x^2-1))/(2x+3) ?
The domain of f(t)=((x^2-1))/(2x+3) is x<-3/2 \lor x>-3/2