What is the domain of f(x)=arccos(1/(x-3)) ?

The domain of f(x)=arccos(1/(x-3)) is x = 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=arccos(1/(x-3))

domain

f (x) = arccos (\frac{1}{x - 3})

x \leq 2 or x \geq 4

Interval Notation

(- \infty, 2] \cup [4, \infty)

Solution steps

Find known functions domain restrictions:

x \leq 2 or x \geq 4

Find undefined (singularity) points:

x = 3

Combine real regions and undefined points for final function domain

x \leq 2 or x \geq 4

f (x) = ln (3 - x)

5 x - 7

f (x) = \frac{x - 3}{x + 5}

y = csc (x)

f (x) = tan (x + \frac{π}{2})

What is the domain of f(x)=arccos(1/(x-3)) ?
The domain of f(x)=arccos(1/(x-3)) is x<= 2\lor x>= 4