What is the domain of f(x)=(x+2)/(\sqrt[8]{49-x^2)} ?

The domain of f(x)=(x+2)/(\sqrt[8]{49-x^2)} is -7<x<7

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domain of f(x)=(x+2)/(\sqrt[8]{49-x^2)}

domain

- 7 < x < 7

Interval Notation

(- 7, 7)

Solution steps

Find non-negative values for radicals:

- 7 \leq x \leq 7

Find undefined (singularity) points:

x = 7, x = - 7

Combine real regions and undefined points for final function domain

- 7 < x < 7

f (x) = x - 3 + \frac{1}{x + 2}

f (x) = \frac{2 x + 5}{x ^{2} + 4 x + 3}

f (x) = 3 x^{2} + 2 x + 1

f (x) = 3^{x - 2}

g (x) = \frac{1}{x}

What is the domain of f(x)=(x+2)/(\sqrt[8]{49-x^2)} ?
The domain of f(x)=(x+2)/(\sqrt[8]{49-x^2)} is -7<x<7