What is the domain of f(x)=sqrt(2-x-x^2) ?

The domain of f(x)=sqrt(2-x-x^2) is -2<= x<= 1

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domain of f(x)=sqrt(2-x-x^2)

domain

f (x) = 2 - x - x^{2}

- 2 \leq x \leq 1

Interval Notation

[- 2, 1]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 1

The function domain

- 2 \leq x \leq 1

y = lo g_{10} (x)

f (x) = ln (ln (x))

f (x) = \frac{1 - x}{x + 2}

f (x) = \frac{25 - x ^{2}}{3 x ^{2} - 12}

f (x) = \frac{x + 1}{x ^{2} - 16}

What is the domain of f(x)=sqrt(2-x-x^2) ?
The domain of f(x)=sqrt(2-x-x^2) is -2<= x<= 1