What is the domain of f(x)= 1/(\sqrt[4]{x^2-4x)} ?

The domain of f(x)= 1/(\sqrt[4]{x^2-4x)} is x 4

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domain of f(x)= 1/(\sqrt[4]{x^2-4x)}

domain

x < 0 or x > 4

Interval Notation

(- \infty, 0) \cup (4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 0 or x \geq 4

Find undefined (singularity) points:

x = 4, x = 0

Combine real regions and undefined points for final function domain

x < 0 or x > 4

f (x) = lo g_{6} (2 x - 4)

f (x) = 9 sin (x - 5) + 8

\frac{x ^{2} - 4}{x ^{2} - 1}

- 2 x + 1

- 2 x

What is the domain of f(x)= 1/(\sqrt[4]{x^2-4x)} ?
The domain of f(x)= 1/(\sqrt[4]{x^2-4x)} is x<0\lor x>4