What is the domain of 4/(y+2)-3/(y-2)+(12)/(y^2-4) ?

The domain of 4/(y+2)-3/(y-2)+(12)/(y^2-4) is y 2

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domain of 4/(y+2)-3/(y-2)+(12)/(y^2-4)

domain

\frac{4}{y + 2} - \frac{3}{y - 2} + \frac{12}{y ^{2} - 4}

y < - 2 or - 2 < y < 2 or y > 2

Interval Notation

(- \infty, - 2) \cup (- 2, 2) \cup (2, \infty)

Solution steps

Find undefined (singularity) points:

y = - 2, y = 2

The function domain

y < - 2 or - 2 < y < 2 or y > 2

lo g_{x} (36 - x^{2})

f (x) = cos (x) - 1

arcsec (x)

ln (x + 4)

f (x) = \frac{1}{x + 3}

What is the domain of 4/(y+2)-3/(y-2)+(12)/(y^2-4) ?
The domain of 4/(y+2)-3/(y-2)+(12)/(y^2-4) is y<-2\lor-2<y<2\lor y>2