What is the domain of f(x)=(x^2-4)/(x-1) ?

The domain of f(x)=(x^2-4)/(x-1) is x 1

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domain of f(x)=(x^2-4)/(x-1)

domain

f (x) = \frac{x ^{2} - 4}{x - 1}

x < 1 or x > 1

Interval Notation

(- \infty, 1) \cup (1, \infty)

Solution steps

Find undefined (singularity) points:

x = 1

The function domain

x < 1 or x > 1

f (x) = \frac{x + 2}{x - 1}

e^{- x^{2}}

f (x) = \frac{x}{x}

\frac{1 - x ^{2}}{x ^{3} + x}

f (x) = (x^{2} + 1) - 1

What is the domain of f(x)=(x^2-4)/(x-1) ?
The domain of f(x)=(x^2-4)/(x-1) is x<1\lor x>1