What is the domain of f(x)=(sin(x))/(1+cos(x)) ?

The domain of f(x)=(sin(x))/(1+cos(x)) is 2pin<= x<pi+2pin\lor pi+2pin<x<2pi+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=(sin(x))/(1+cos(x))

domain

f (x) = \frac{sin ( x )}{1 + cos ( x )}

2 πn \leq x < π + 2 πn or π + 2 πn < x < 2 π + 2 πn

Interval Notation

[2 πn, π + 2 πn) \cup (π + 2 πn, 2 π + 2 πn)

Solution steps

Take the denominator(s) of

\frac{sin ( x )}{1 + cos ( x )}

and compare to zero:

x = π + 2 πn

Periodicity of

\frac{sin ( x )}{1 + cos ( x )} : 2 π

Combine period:

2 πn \leq x < 2 π + 2 πn

and undefined points.

The domain is

2 πn \leq x < π + 2 πn or π + 2 πn < x < 2 π + 2 πn

- 3

f (x) = \frac{x + 5}{2 x - 4}

f (x) = lo g_{10} (x - 5)

f (x) = - x^{2} + 18 x - 1

sinh (x)

What is the domain of f(x)=(sin(x))/(1+cos(x)) ?
The domain of f(x)=(sin(x))/(1+cos(x)) is 2pin<= x<pi+2pin\lor pi+2pin<x<2pi+2pin